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5110066735493 is a prime number
BaseRepresentation
bin100101001011100011110…
…1101100110100110000101
3200002111222100002121200012
41022113013231212212011
51132210404041013433
614511310544400005
71035122134401536
oct112270755464605
920074870077605
105110066735493
1116a01924a8a75
126a6447016005
132b0b53358b15
1413948577c68d
158cdd05ec848
hex4a5c7b66985

5110066735493 has 2 divisors, whose sum is σ = 5110066735494. Its totient is φ = 5110066735492.

The previous prime is 5110066735471. The next prime is 5110066735507. The reversal of 5110066735493 is 3945376600115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5090627962564 + 19438772929 = 2256242^2 + 139423^2 .

It is a cyclic number.

It is not a de Polignac number, because 5110066735493 - 210 = 5110066734469 is a prime.

It is a super-2 number, since 2×51100667354932 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5110066725493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555033367746 + 2555033367747.

It is an arithmetic number, because the mean of its divisors is an integer number (2555033367747).

Almost surely, 25110066735493 is an apocalyptic number.

It is an amenable number.

5110066735493 is a deficient number, since it is larger than the sum of its proper divisors (1).

5110066735493 is an equidigital number, since it uses as much as digits as its factorization.

5110066735493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2041200, while the sum is 50.

The spelling of 5110066735493 in words is "five trillion, one hundred ten billion, sixty-six million, seven hundred thirty-five thousand, four hundred ninety-three".