Base | Representation |
---|---|
bin | 100101001011100100111… |
… | …0010011000011010010111 |
3 | 200002112001202120222222111 |
4 | 1022113021302120122113 |
5 | 1132210441443330201 |
6 | 14511314230411451 |
7 | 1035123036301045 |
oct | 112271162303227 |
9 | 20075052528874 |
10 | 5110101542551 |
11 | 16a0200112035 |
12 | 6a6456800b87 |
13 | 2b0b5a624b05 |
14 | 13948a23d395 |
15 | 8cdd36c5b51 |
hex | 4a5c9c98697 |
5110101542551 has 32 divisors (see below), whose sum is σ = 5656639887360. Its totient is φ = 4599653313024.
The previous prime is 5110101542527. The next prime is 5110101542569. The reversal of 5110101542551 is 1552451010115.
It is a cyclic number.
It is not a de Polignac number, because 5110101542551 - 25 = 5110101542519 is a prime.
It is a super-2 number, since 2×51101015425512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110101242551) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13086895 + ... + 13471711.
It is an arithmetic number, because the mean of its divisors is an integer number (176769996480).
Almost surely, 25110101542551 is an apocalyptic number.
5110101542551 is a deficient number, since it is larger than the sum of its proper divisors (546538344809).
5110101542551 is a wasteful number, since it uses less digits than its factorization.
5110101542551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 385375.
The product of its (nonzero) digits is 5000, while the sum is 31.
Adding to 5110101542551 its reverse (1552451010115), we get a palindrome (6662552552666).
The spelling of 5110101542551 in words is "five trillion, one hundred ten billion, one hundred one million, five hundred forty-two thousand, five hundred fifty-one".
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