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51101106551 = 1129363125127
BaseRepresentation
bin101111100101110111…
…010000000101110111
311212220022202011211222
4233211313100011313
51314123340402201
635250414020555
73456222144635
oct574567200567
9155808664758
1051101106551
111a743273770
129aa17a775b
134a84c1a271
14268aa7a355
1514e139891b
hexbe5dd0177

51101106551 has 16 divisors (see below), whose sum is σ = 56027801088. Its totient is φ = 46221789600.

The previous prime is 51101106541. The next prime is 51101106557. The reversal of 51101106551 is 15560110115.

It is a cyclic number.

It is not a de Polignac number, because 51101106551 - 222 = 51096912247 is a prime.

It is a super-2 number, since 2×511011065512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 51101106551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51101106557) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2021150 + ... + 2046276.

It is an arithmetic number, because the mean of its divisors is an integer number (3501737568).

Almost surely, 251101106551 is an apocalyptic number.

51101106551 is a deficient number, since it is larger than the sum of its proper divisors (4926694537).

51101106551 is a wasteful number, since it uses less digits than its factorization.

51101106551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26062.

The product of its (nonzero) digits is 750, while the sum is 26.

Adding to 51101106551 its reverse (15560110115), we get a palindrome (66661216666).

The spelling of 51101106551 in words is "fifty-one billion, one hundred one million, one hundred six thousand, five hundred fifty-one".

Divisors: 1 11 293 631 3223 6941 25127 184883 276397 2033713 7362211 15855137 80984321 174406507 4645555141 51101106551