Base | Representation |
---|---|
bin | 100101001011100101010… |
… | …0110000100101110101111 |
3 | 200002112002201002110021122 |
4 | 1022113022212010232233 |
5 | 1132211003430442143 |
6 | 14511315433051155 |
7 | 1035123262420004 |
oct | 112271246045657 |
9 | 20075081073248 |
10 | 5110115093423 |
11 | 16a0207827aaa |
12 | 6a645b256abb |
13 | 2b0b6038a992 |
14 | 13948bd698ab |
15 | 8cdd49a0c68 |
hex | 4a5ca984baf |
5110115093423 has 2 divisors, whose sum is σ = 5110115093424. Its totient is φ = 5110115093422.
The previous prime is 5110115093401. The next prime is 5110115093437. The reversal of 5110115093423 is 3243905110115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5110115093423 - 240 = 4010603465647 is a prime.
It is a super-2 number, since 2×51101150934232 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5110115093023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555057546711 + 2555057546712.
It is an arithmetic number, because the mean of its divisors is an integer number (2555057546712).
Almost surely, 25110115093423 is an apocalyptic number.
5110115093423 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110115093423 is an equidigital number, since it uses as much as digits as its factorization.
5110115093423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 35.
The spelling of 5110115093423 in words is "five trillion, one hundred ten billion, one hundred fifteen million, ninety-three thousand, four hundred twenty-three".
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