Base | Representation |
---|---|
bin | 1001100001001011… |
… | …10111110011111101 |
3 | 111012010202010201211 |
4 | 10300211313303331 |
5 | 40431202422342 |
6 | 2203025204421 |
7 | 240430665634 |
oct | 46045676375 |
9 | 14163663654 |
10 | 5110201597 |
11 | 2192637106 |
12 | ba7490711 |
13 | 635934937 |
14 | 36698a51b |
15 | 1ed973c17 |
hex | 130977cfd |
5110201597 has 2 divisors, whose sum is σ = 5110201598. Its totient is φ = 5110201596.
The previous prime is 5110201589. The next prime is 5110201631. The reversal of 5110201597 is 7951020115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3207409956 + 1902791641 = 56634^2 + 43621^2 .
It is a cyclic number.
It is not a de Polignac number, because 5110201597 - 23 = 5110201589 is a prime.
It is a super-3 number, since 3×51102015973 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5110201507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555100798 + 2555100799.
It is an arithmetic number, because the mean of its divisors is an integer number (2555100799).
Almost surely, 25110201597 is an apocalyptic number.
It is an amenable number.
5110201597 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110201597 is an equidigital number, since it uses as much as digits as its factorization.
5110201597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3150, while the sum is 31.
The square root of 5110201597 is about 71485.6740683055. The cubic root of 5110201597 is about 1722.4475697285.
The spelling of 5110201597 in words is "five billion, one hundred ten million, two hundred one thousand, five hundred ninety-seven".
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