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5110233121543 = 11276954919807
BaseRepresentation
bin100101001011101000110…
…1000010100001100000111
3200002112101221011220102111
41022113101220110030013
51132211224134342133
614511335250521451
71035126224556214
oct112272150241407
920075357156374
105110233121543
1116a0268412300
126a6492896287
132b0b7b9741c4
1413949d8d0b0b
158cde00171cd
hex4a5d1a14307

5110233121543 has 12 divisors (see below), whose sum is σ = 5624337537280. Its totient is φ = 4639625210880.

The previous prime is 5110233121517. The next prime is 5110233121571. The reversal of 5110233121543 is 3451213320115.

It is not a de Polignac number, because 5110233121543 - 237 = 4972794168071 is a prime.

It is a super-2 number, since 2×51102331215432 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5110233131543) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27366855 + ... + 27552952.

Almost surely, 25110233121543 is an apocalyptic number.

5110233121543 is a deficient number, since it is larger than the sum of its proper divisors (514104415737).

5110233121543 is a wasteful number, since it uses less digits than its factorization.

5110233121543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54920598 (or 54920587 counting only the distinct ones).

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 5110233121543 its reverse (3451213320115), we get a palindrome (8561446441658).

The spelling of 5110233121543 in words is "five trillion, one hundred ten billion, two hundred thirty-three million, one hundred twenty-one thousand, five hundred forty-three".

Divisors: 1 11 121 769 8459 93049 54919807 604117877 6645296647 42233331583 464566647413 5110233121543