Base | Representation |
---|---|
bin | 1110110111110111101… |
… | …10001011000110110100 |
3 | 1210212001122210002022000 |
4 | 13123323312023012310 |
5 | 31333043021022122 |
6 | 1030433052535300 |
7 | 51630556266546 |
oct | 7337366130664 |
9 | 1725048702260 |
10 | 511031423412 |
11 | 1877aaa09154 |
12 | 8305b481530 |
13 | 39261728253 |
14 | 1aa3c353696 |
15 | d45e32d0ac |
hex | 76fbd8b1b4 |
511031423412 has 48 divisors (see below), whose sum is σ = 1324966944000. Its totient is φ = 170334722880.
The previous prime is 511031423407. The next prime is 511031423503. The reversal of 511031423412 is 214324130115.
511031423412 is a `hidden beast` number, since 5 + 1 + 1 + 0 + 314 + 2 + 341 + 2 = 666.
It is a super-2 number, since 2×5110314234122 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2087112 + ... + 2319072.
It is an arithmetic number, because the mean of its divisors is an integer number (27603478000).
Almost surely, 2511031423412 is an apocalyptic number.
It is an amenable number.
511031423412 is an abundant number, since it is smaller than the sum of its proper divisors (813935520588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
511031423412 is a wasteful number, since it uses less digits than its factorization.
511031423412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252373 (or 252365 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 511031423412 its reverse (214324130115), we get a palindrome (725355553527).
The spelling of 511031423412 in words is "five hundred eleven billion, thirty-one million, four hundred twenty-three thousand, four hundred twelve".
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