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5110333445542 = 213712768327977
BaseRepresentation
bin100101001011101011110…
…0111000001010110100110
3200002112122220221220002011
41022113113213001112212
51132211430330224132
614511353233104434
71035131553401053
oct112272747012646
920075586856064
105110333445542
1116a030a0051a6
126a65003b811a
132b0b9669c310
141394acd6802a
158cde8c32b47
hex4a5d79c15a6

5110333445542 has 16 divisors (see below), whose sum is σ = 8371423805472. Its totient is φ = 2325395499840.

The previous prime is 5110333445533. The next prime is 5110333445579. The reversal of 5110333445542 is 2455443330115.

It is a super-2 number, since 2×51103334455422 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5110333445495 and 5110333445504.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1384162143 + ... + 1384165834.

It is an arithmetic number, because the mean of its divisors is an integer number (523213987842).

Almost surely, 25110333445542 is an apocalyptic number.

5110333445542 is a deficient number, since it is larger than the sum of its proper divisors (3261090359930).

5110333445542 is a wasteful number, since it uses less digits than its factorization.

5110333445542 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2768328063.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 5110333445542 its reverse (2455443330115), we get a palindrome (7565776775657).

The spelling of 5110333445542 in words is "five trillion, one hundred ten billion, three hundred thirty-three million, four hundred forty-five thousand, five hundred forty-two".

Divisors: 1 2 13 26 71 142 923 1846 2768327977 5536655954 35988263701 71976527402 196551286367 393102572734 2555166722771 5110333445542