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51103431333404 = 2236929345957319
BaseRepresentation
bin10111001111010011100011…
…10111110001011000011100
320200221102212222212211101222
423213221301313301120130
523144234311410132104
6300404331532152512
713523046445124132
oct1347516167613034
9220842788784358
1051103431333404
11153129307a670a
12589422b908738
132269057374c38
14c895c26b7752
155d94b69a71be
hex2e7a71df161c

51103431333404 has 12 divisors (see below), whose sum is σ = 89433426793200. Its totient is φ = 25551023678208.

The previous prime is 51103431333379. The next prime is 51103431333523. The reversal of 51103431333404 is 40433313430115.

It is a super-2 number, since 2×511034313334042 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172830944 + ... + 173126375.

It is an arithmetic number, because the mean of its divisors is an integer number (7452785566100).

Almost surely, 251103431333404 is an apocalyptic number.

It is an amenable number.

51103431333404 is a deficient number, since it is larger than the sum of its proper divisors (38329995459796).

51103431333404 is a wasteful number, since it uses less digits than its factorization.

51103431333404 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 345994252 (or 345994250 counting only the distinct ones).

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 51103431333404 its reverse (40433313430115), we get a palindrome (91536744763519).

The spelling of 51103431333404 in words is "fifty-one trillion, one hundred three billion, four hundred thirty-one million, three hundred thirty-three thousand, four hundred four".

Divisors: 1 2 4 36929 73858 147716 345957319 691914638 1383829276 12775857833351 25551715666702 51103431333404