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51104134121 is a prime number
BaseRepresentation
bin101111100110000010…
…110011001111101001
311212220112102222220012
4233212002303033221
51314130124242441
635251002541305
73456256654445
oct574602631751
9155815388805
1051104134121
111a744a51397
129aa2807835
134a8573a321
14268b227825
1514e17959eb
hexbe60b33e9

51104134121 has 2 divisors, whose sum is σ = 51104134122. Its totient is φ = 51104134120.

The previous prime is 51104134091. The next prime is 51104134181. The reversal of 51104134121 is 12143140115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38235500521 + 12868633600 = 195539^2 + 113440^2 .

It is a cyclic number.

It is not a de Polignac number, because 51104134121 - 230 = 50030392297 is a prime.

It is a super-2 number, since 2×511041341212 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51104134181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25552067060 + 25552067061.

It is an arithmetic number, because the mean of its divisors is an integer number (25552067061).

Almost surely, 251104134121 is an apocalyptic number.

It is an amenable number.

51104134121 is a deficient number, since it is larger than the sum of its proper divisors (1).

51104134121 is an equidigital number, since it uses as much as digits as its factorization.

51104134121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 51104134121 its reverse (12143140115), we get a palindrome (63247274236).

The spelling of 51104134121 in words is "fifty-one billion, one hundred four million, one hundred thirty-four thousand, one hundred twenty-one".