Base | Representation |
---|---|
bin | 1100001011110… |
… | …0110000011001 |
3 | 10120011101121010 |
4 | 3002330300121 |
5 | 101040323133 |
6 | 5023204133 |
7 | 1160245365 |
oct | 302746031 |
9 | 116141533 |
10 | 51104793 |
11 | 26935873 |
12 | 15146649 |
13 | a78422c |
14 | 6b042a5 |
15 | 4747263 |
hex | 30bcc19 |
51104793 has 4 divisors (see below), whose sum is σ = 68139728. Its totient is φ = 34069860.
The previous prime is 51104783. The next prime is 51104821. The reversal of 51104793 is 39740115.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 51104793 - 25 = 51104761 is a prime.
It is a super-3 number, since 3×511047933 (a number of 24 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 51104793.
It is not an unprimeable number, because it can be changed into a prime (51104723) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8517463 + ... + 8517468.
It is an arithmetic number, because the mean of its divisors is an integer number (17034932).
Almost surely, 251104793 is an apocalyptic number.
It is an amenable number.
51104793 is a deficient number, since it is larger than the sum of its proper divisors (17034935).
51104793 is a wasteful number, since it uses less digits than its factorization.
51104793 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17034934.
The product of its (nonzero) digits is 3780, while the sum is 30.
The square root of 51104793 is about 7148.7616410117. The cubic root of 51104793 is about 371.0968015095.
The spelling of 51104793 in words is "fifty-one million, one hundred four thousand, seven hundred ninety-three".
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