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51105134003 = 7114116187879
BaseRepresentation
bin101111100110000110…
…100111010110110011
311212220121022210110212
4233212012213112303
51314130403242003
635251040214335
73456301320530
oct574606472663
9155817283425
1051105134003
111a745574640
129aa300a3ab
134a859ca481
14268b407d87
1514e18e1dd8
hexbe61a75b3

51105134003 has 16 divisors (see below), whose sum is σ = 65269532160. Its totient is φ = 38850907200.

The previous prime is 51105133997. The next prime is 51105134009. The reversal of 51105134003 is 30043150115.

It is an interprime number because it is at equal distance from previous prime (51105133997) and next prime (51105134009).

It is a de Polignac number, because none of the positive numbers 2k-51105134003 is a prime.

It is a super-2 number, since 2×511051340032 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51105134003.

It is not an unprimeable number, because it can be changed into a prime (51105134009) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8090783 + ... + 8097096.

It is an arithmetic number, because the mean of its divisors is an integer number (4079345760).

Almost surely, 251105134003 is an apocalyptic number.

51105134003 is a deficient number, since it is larger than the sum of its proper divisors (14164398157).

51105134003 is a wasteful number, since it uses less digits than its factorization.

51105134003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16187938.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 51105134003 its reverse (30043150115), we get a palindrome (81148284118).

The spelling of 51105134003 in words is "fifty-one billion, one hundred five million, one hundred thirty-four thousand, three".

Divisors: 1 7 11 41 77 287 451 3157 16187879 113315153 178066669 663703039 1246466683 4645921273 7300733429 51105134003