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51105425120653 is a prime number
BaseRepresentation
bin10111001111010111010001…
…01101011101110110001101
320200221122000221112201100011
423213223220231131312031
523144302402312330103
6300405301434033221
713523150035052011
oct1347535055356615
9220848027481304
1051105425120653
111531376418a572
1258946a7578811
1322692b44554c7
14c897313d6541
155d9581a3dd6d
hex2e7ae8b5dd8d

51105425120653 has 2 divisors, whose sum is σ = 51105425120654. Its totient is φ = 51105425120652.

The previous prime is 51105425120641. The next prime is 51105425120803. The reversal of 51105425120653 is 35602152450115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33853057082244 + 17252368038409 = 5818338^2 + 4153597^2 .

It is a cyclic number.

It is not a de Polignac number, because 51105425120653 - 213 = 51105425112461 is a prime.

It is a super-2 number, since 2×511054251206532 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51105425120623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25552712560326 + 25552712560327.

It is an arithmetic number, because the mean of its divisors is an integer number (25552712560327).

Almost surely, 251105425120653 is an apocalyptic number.

It is an amenable number.

51105425120653 is a deficient number, since it is larger than the sum of its proper divisors (1).

51105425120653 is an equidigital number, since it uses as much as digits as its factorization.

51105425120653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 40.

Adding to 51105425120653 its reverse (35602152450115), we get a palindrome (86707577570768).

The spelling of 51105425120653 in words is "fifty-one trillion, one hundred five billion, four hundred twenty-five million, one hundred twenty thousand, six hundred fifty-three".