Base | Representation |
---|---|
bin | 10111001111011000011011… |
… | …00110100010000111010011 |
3 | 20200221200122002012002122221 |
4 | 23213230031212202013103 |
5 | 23144310134234410430 |
6 | 300405443104041511 |
7 | 13523201262002152 |
oct | 1347541546420723 |
9 | 220850562162587 |
10 | 51106044060115 |
11 | 15313a515a3990 |
12 | 589483a903297 |
13 | 2269382752885 |
14 | c8978d6ad599 |
15 | 5d95bb04d57a |
hex | 2e7b0d9a21d3 |
51106044060115 has 32 divisors (see below), whose sum is σ = 68543326353600. Its totient is φ = 36256679116800.
The previous prime is 51106044060101. The next prime is 51106044060133.
51106044060115 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 51106044060115 - 25 = 51106044060083 is a prime.
It is a super-2 number, since 2×511060440601152 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15521907 + ... + 18524083.
It is an arithmetic number, because the mean of its divisors is an integer number (2141978948550).
Almost surely, 251106044060115 is an apocalyptic number.
51106044060115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51106044060115 is a deficient number, since it is larger than the sum of its proper divisors (17437282293485).
51106044060115 is a wasteful number, since it uses less digits than its factorization.
51106044060115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3009783.
The product of its (nonzero) digits is 14400, while the sum is 34.
It can be divided in two parts, 5110604 and 4060115, that added together give a palindrome (9170719).
The spelling of 51106044060115 in words is "fifty-one trillion, one hundred six billion, forty-four million, sixty thousand, one hundred fifteen".
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