Base | Representation |
---|---|
bin | 100101001011111111111… |
… | …1111101101010001101011 |
3 | 200002121102010220111200011 |
4 | 1022113333333231101223 |
5 | 1132214322304134142 |
6 | 14511544355352351 |
7 | 1035154421511466 |
oct | 112277777552153 |
9 | 20077363814604 |
10 | 5111011005547 |
11 | 16a0627518047 |
12 | 6a666b2b26b7 |
13 | 2b0c73b827b5 |
14 | 139534d402dd |
15 | 8ce38471417 |
hex | 4a5fffed46b |
5111011005547 has 4 divisors (see below), whose sum is σ = 5111027176096. Its totient is φ = 5110994835000.
The previous prime is 5111011005473. The next prime is 5111011005613. The reversal of 5111011005547 is 7455001101115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5111011005547 - 235 = 5076651267179 is a prime.
It is a super-2 number, since 2×51110110055472 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5111011005647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7601523 + ... + 8246524.
It is an arithmetic number, because the mean of its divisors is an integer number (1277756794024).
Almost surely, 25111011005547 is an apocalyptic number.
5111011005547 is a deficient number, since it is larger than the sum of its proper divisors (16170549).
5111011005547 is a wasteful number, since it uses less digits than its factorization.
5111011005547 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16170548.
The product of its (nonzero) digits is 3500, while the sum is 31.
The spelling of 5111011005547 in words is "five trillion, one hundred eleven billion, eleven million, five thousand, five hundred forty-seven".
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