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5110994835000 = 233354174367773
BaseRepresentation
bin100101001011111111100…
…0010000001011000111000
3200002121101000110221212000
41022113333002001120320
51132214304134210000
614511543021021000
71035154134202155
oct112277702013070
920077330427760
105110994835000
1116a061938295a
126a66659b4760
132b0c70710422
14139532b3122c
158ce36d2a000
hex4a5ff081638

5110994835000 has 1280 divisors, whose sum is σ = 19533377318400. Its totient is φ = 1232630784000.

The previous prime is 5110994834993. The next prime is 5110994835007. The reversal of 5110994835000 is 5384990115.

5110994835000 is a `hidden beast` number, since 5 + 1 + 10 + 99 + 48 + 3 + 500 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (5110994834993) and next prime (5110994835007).

It is a super-3 number, since 3×51109948350003 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5110994835007) by changing a digit.

It is a polite number, since it can be written in 319 ways as a sum of consecutive naturals, for example, 6611894614 + ... + 6611895386.

It is an arithmetic number, because the mean of its divisors is an integer number (15260451030).

Almost surely, 25110994835000 is an apocalyptic number.

5110994835000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5110994835000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (9766688659200).

5110994835000 is an abundant number, since it is smaller than the sum of its proper divisors (14422382483400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5110994835000 is a wasteful number, since it uses less digits than its factorization.

5110994835000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 935 (or 910 counting only the distinct ones).

The product of its (nonzero) digits is 194400, while the sum is 45.

The spelling of 5110994835000 in words is "five trillion, one hundred ten billion, nine hundred ninety-four million, eight hundred thirty-five thousand".