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51112371421 is a prime number
BaseRepresentation
bin101111100110100010…
…001110010011011101
311212221002221111100101
4233212202032103131
51314134231341141
635251455301101
73456416663056
oct574642162335
9155832844311
1051112371421
111a749668181
129aa551a791
134a87362777
14268c36d72d
1514e2371531
hexbe688e4dd

51112371421 has 2 divisors, whose sum is σ = 51112371422. Its totient is φ = 51112371420.

The previous prime is 51112371407. The next prime is 51112371463. The reversal of 51112371421 is 12417321115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42214222521 + 8898148900 = 205461^2 + 94330^2 .

It is a cyclic number.

It is not a de Polignac number, because 51112371421 - 27 = 51112371293 is a prime.

It is a super-2 number, since 2×511123714212 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51112371421.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51112371481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556185710 + 25556185711.

It is an arithmetic number, because the mean of its divisors is an integer number (25556185711).

Almost surely, 251112371421 is an apocalyptic number.

It is an amenable number.

51112371421 is a deficient number, since it is larger than the sum of its proper divisors (1).

51112371421 is an equidigital number, since it uses as much as digits as its factorization.

51112371421 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1680, while the sum is 28.

Adding to 51112371421 its reverse (12417321115), we get a palindrome (63529692536).

The spelling of 51112371421 in words is "fifty-one billion, one hundred twelve million, three hundred seventy-one thousand, four hundred twenty-one".