5111254404033 has 4 divisors (see below), whose sum is σ = 6815005872048. Its totient is φ = 3407502936020.

The previous prime is 5111254404031. The next prime is 5111254404071. The reversal of 5111254404033 is 3304044521115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5111254404033 - 2¹ = 5111254404031 is a prime.

It is a super-2 number, since 2×5111254404033² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5111254403985 and 5111254404003.

It is not an unprimeable number, because it can be changed into a prime (5111254404031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 851875734003 + ... + 851875734008.

It is an arithmetic number, because the mean of its divisors is an integer number (1703751468012).

Almost surely, 2^{5111254404033} is an apocalyptic number.

It is an amenable number.

5111254404033 is a deficient number, since it is larger than the sum of its proper divisors (1703751468015).

5111254404033 is a wasteful number, since it uses less digits than its factorization.

5111254404033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1703751468014.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 5111254404033 its reverse (3304044521115), we get a palindrome (8415298925148).

The spelling of 5111254404033 in words is "five trillion, one hundred eleven billion, two hundred fifty-four million, four hundred four thousand, thirty-three".