51113001 has 4 divisors (see below), whose sum is σ = 68150672. Its totient is φ = 34075332.

The previous prime is 51112987. The next prime is 51113003. The reversal of 51113001 is 10031115.

51113001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 51113001 - 2¹¹ = 51110953 is a prime.

It is a super-2 number, since 2×51113001² = 5225077742452002, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51113003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8518831 + ... + 8518836.

It is an arithmetic number, because the mean of its divisors is an integer number (17037668).

Almost surely, 2^51113001 is an apocalyptic number.

It is an amenable number.

51113001 is a deficient number, since it is larger than the sum of its proper divisors (17037671).

51113001 is a wasteful number, since it uses less digits than its factorization.

51113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17037670.

The product of its (nonzero) digits is 15, while the sum is 12.

The square root of 51113001 is about 7149.3357034063. The cubic root of 51113001 is about 371.1166678750.

Adding to 51113001 its reverse (10031115), we get a palindrome (61144116).

The spelling of 51113001 in words is "fifty-one million, one hundred thirteen thousand, one".