Base | Representation |
---|---|
bin | 101111100110100100… |
… | …101111011100001111 |
3 | 11212221011012000201111 |
4 | 233212210233130033 |
5 | 1314134414001224 |
6 | 35251521352451 |
7 | 3456425412241 |
oct | 574644573417 |
9 | 155834160644 |
10 | 51113031439 |
11 | 1a749a79048 |
12 | 9aa5798727 |
13 | 4a87534002 |
14 | 268c4a2091 |
15 | 14e2451d94 |
hex | be692f70f |
51113031439 has 2 divisors, whose sum is σ = 51113031440. Its totient is φ = 51113031438.
The previous prime is 51113031391. The next prime is 51113031443. The reversal of 51113031439 is 93413031115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51113031439 - 211 = 51113029391 is a prime.
It is a super-2 number, since 2×511130314392 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 51113031439.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51113031479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556515719 + 25556515720.
It is an arithmetic number, because the mean of its divisors is an integer number (25556515720).
Almost surely, 251113031439 is an apocalyptic number.
51113031439 is a deficient number, since it is larger than the sum of its proper divisors (1).
51113031439 is an equidigital number, since it uses as much as digits as its factorization.
51113031439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 31.
The spelling of 51113031439 in words is "fifty-one billion, one hundred thirteen million, thirty-one thousand, four hundred thirty-nine".
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