Base | Representation |
---|---|
bin | 101111100110100101… |
… | …010110110101111111 |
3 | 11212221011111020002222 |
4 | 233212211112311333 |
5 | 1314134434132311 |
6 | 35251525035555 |
7 | 3456426653621 |
oct | 574645266577 |
9 | 155834436088 |
10 | 51113192831 |
11 | 1a74a079328 |
12 | 9aa5855bbb |
13 | 4a8758c5cc |
14 | 268c504c11 |
15 | 14e2484adb |
hex | be6956d7f |
51113192831 has 2 divisors, whose sum is σ = 51113192832. Its totient is φ = 51113192830.
The previous prime is 51113192737. The next prime is 51113192849. The reversal of 51113192831 is 13829131115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51113192831 - 214 = 51113176447 is a prime.
It is a super-2 number, since 2×511131928312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51113192791 and 51113192800.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51113192861) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556596415 + 25556596416.
It is an arithmetic number, because the mean of its divisors is an integer number (25556596416).
Almost surely, 251113192831 is an apocalyptic number.
51113192831 is a deficient number, since it is larger than the sum of its proper divisors (1).
51113192831 is an equidigital number, since it uses as much as digits as its factorization.
51113192831 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 35.
The spelling of 51113192831 in words is "fifty-one billion, one hundred thirteen million, one hundred ninety-two thousand, eight hundred thirty-one".
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