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51113192833 = 479111795531
BaseRepresentation
bin101111100110100101…
…010110110110000001
311212221011111020010001
4233212211112312001
51314134434132313
635251525040001
73456426653623
oct574645266601
9155834436101
1051113192833
111a74a07932a
129aa5856001
134a8758c601
14268c504c13
1514e2484add
hexbe6956d81

51113192833 has 8 divisors (see below), whose sum is σ = 51266292480. Its totient is φ = 50960287440.

The previous prime is 51113192831. The next prime is 51113192849. The reversal of 51113192833 is 33829131115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51113192833 - 21 = 51113192831 is a prime.

It is a super-2 number, since 2×511131928332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51113192792 and 51113192801.

It is not an unprimeable number, because it can be changed into a prime (51113192831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 487278 + ... + 582808.

It is an arithmetic number, because the mean of its divisors is an integer number (6408286560).

Almost surely, 251113192833 is an apocalyptic number.

It is an amenable number.

51113192833 is a deficient number, since it is larger than the sum of its proper divisors (153099647).

51113192833 is a wasteful number, since it uses less digits than its factorization.

51113192833 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97127.

The product of its digits is 19440, while the sum is 37.

The spelling of 51113192833 in words is "fifty-one billion, one hundred thirteen million, one hundred ninety-two thousand, eight hundred thirty-three".

Divisors: 1 479 1117 95531 535043 45759349 106708127 51113192833