Base | Representation |
---|---|
bin | 100101001100001001010… |
… | …1110111110110010111111 |
3 | 200002122020001110210021111 |
4 | 1022120102232332302333 |
5 | 1132220443244403332 |
6 | 14512035505542451 |
7 | 1035165256642351 |
oct | 112302256766277 |
9 | 20078201423244 |
10 | 5111325387967 |
11 | 16a0778a25227 |
12 | 6a6738644a27 |
13 | 2b0cc4047ab6 |
14 | 1395649b90d1 |
15 | 8ce55d71947 |
hex | 4a612bbecbf |
5111325387967 has 2 divisors, whose sum is σ = 5111325387968. Its totient is φ = 5111325387966.
The previous prime is 5111325387929. The next prime is 5111325388021. The reversal of 5111325387967 is 7697835231115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5111325387967 - 211 = 5111325385919 is a prime.
It is a super-2 number, since 2×51113253879672 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5111325187967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555662693983 + 2555662693984.
It is an arithmetic number, because the mean of its divisors is an integer number (2555662693984).
Almost surely, 25111325387967 is an apocalyptic number.
5111325387967 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111325387967 is an equidigital number, since it uses as much as digits as its factorization.
5111325387967 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9525600, while the sum is 58.
The spelling of 5111325387967 in words is "five trillion, one hundred eleven billion, three hundred twenty-five million, three hundred eighty-seven thousand, nine hundred sixty-seven".
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