Base | Representation |
---|---|
bin | 101111100110100101… |
… | …110001100100111101 |
3 | 11212221011200210022121 |
4 | 233212211301210331 |
5 | 1314140001133313 |
6 | 35251531242541 |
7 | 3456430621102 |
oct | 574645614475 |
9 | 155834623277 |
10 | 51113302333 |
11 | 1a74a143625 |
12 | 9aa58a9451 |
13 | 4a875ca3c2 |
14 | 268c532aa9 |
15 | 14e24a728d |
hex | be697193d |
51113302333 has 16 divisors (see below), whose sum is σ = 54551584000. Its totient is φ = 47751342912.
The previous prime is 51113302321. The next prime is 51113302349. The reversal of 51113302333 is 33320331115.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51113302333 is a prime.
It is a super-2 number, since 2×511133023332 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51113302298 and 51113302307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51113300333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1223791 + ... + 1264867.
It is an arithmetic number, because the mean of its divisors is an integer number (3409474000).
Almost surely, 251113302333 is an apocalyptic number.
It is an amenable number.
51113302333 is a deficient number, since it is larger than the sum of its proper divisors (3438281667).
51113302333 is a wasteful number, since it uses less digits than its factorization.
51113302333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42004.
The product of its (nonzero) digits is 2430, while the sum is 25.
Adding to 51113302333 its reverse (33320331115), we get a palindrome (84433633448).
The spelling of 51113302333 in words is "fifty-one billion, one hundred thirteen million, three hundred two thousand, three hundred thirty-three".
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