Base | Representation |
---|---|
bin | 101111100110100101… |
… | …110001100101001101 |
3 | 11212221011200210100012 |
4 | 233212211301211031 |
5 | 1314140001133344 |
6 | 35251531243005 |
7 | 3456430621124 |
oct | 574645614515 |
9 | 155834623305 |
10 | 51113302349 |
11 | 1a74a14363a |
12 | 9aa58a9465 |
13 | 4a875ca405 |
14 | 268c532abb |
15 | 14e24a729e |
hex | be697194d |
51113302349 has 2 divisors, whose sum is σ = 51113302350. Its totient is φ = 51113302348.
The previous prime is 51113302321. The next prime is 51113302421. The reversal of 51113302349 is 94320331115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49655437225 + 1457865124 = 222835^2 + 38182^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51113302349 is a prime.
It is a super-2 number, since 2×511133023492 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51113302319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556651174 + 25556651175.
It is an arithmetic number, because the mean of its divisors is an integer number (25556651175).
Almost surely, 251113302349 is an apocalyptic number.
It is an amenable number.
51113302349 is a deficient number, since it is larger than the sum of its proper divisors (1).
51113302349 is an equidigital number, since it uses as much as digits as its factorization.
51113302349 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 32.
The spelling of 51113302349 in words is "fifty-one billion, one hundred thirteen million, three hundred two thousand, three hundred forty-nine".
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