Base | Representation |
---|---|
bin | 100101001100001001100… |
… | …1111111101001010101111 |
3 | 200002122020122201221201121 |
4 | 1022120103033331022233 |
5 | 1132221003003011142 |
6 | 14512040415121411 |
7 | 1035165423263635 |
oct | 112302317751257 |
9 | 20078218657647 |
10 | 5111334032047 |
11 | 16a07828996a1 |
12 | 6a673b513267 |
13 | 2b0cc5a83439 |
14 | 139565bc9355 |
15 | 8ce569ccc67 |
hex | 4a6133fd2af |
5111334032047 has 2 divisors, whose sum is σ = 5111334032048. Its totient is φ = 5111334032046.
The previous prime is 5111334032033. The next prime is 5111334032093. The reversal of 5111334032047 is 7402304331115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5111334032047 - 215 = 5111333999279 is a prime.
It is a super-2 number, since 2×51113340320472 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5111334032747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555667016023 + 2555667016024.
It is an arithmetic number, because the mean of its divisors is an integer number (2555667016024).
Almost surely, 25111334032047 is an apocalyptic number.
5111334032047 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111334032047 is an equidigital number, since it uses as much as digits as its factorization.
5111334032047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 34.
The spelling of 5111334032047 in words is "five trillion, one hundred eleven billion, three hundred thirty-four million, thirty-two thousand, forty-seven".
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