Base | Representation |
---|---|
bin | 100101001100001011100… |
… | …1101100100001100010111 |
3 | 200002122102021211121021021 |
4 | 1022120113031210030113 |
5 | 1132221122012424302 |
6 | 14512051152102011 |
7 | 1035200161336552 |
oct | 112302715441427 |
9 | 20078367747237 |
10 | 5111400514327 |
11 | 16a0807377828 |
12 | 6a6759834907 |
13 | 2b100678ca73 |
14 | 139570973699 |
15 | 8ce5c761437 |
hex | 4a617364317 |
5111400514327 has 2 divisors, whose sum is σ = 5111400514328. Its totient is φ = 5111400514326.
The previous prime is 5111400514303. The next prime is 5111400514373. The reversal of 5111400514327 is 7234150041115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5111400514327 - 215 = 5111400481559 is a prime.
It is a super-2 number, since 2×51114005143272 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5111400514292 and 5111400514301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5111400514427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555700257163 + 2555700257164.
It is an arithmetic number, because the mean of its divisors is an integer number (2555700257164).
Almost surely, 25111400514327 is an apocalyptic number.
5111400514327 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111400514327 is an equidigital number, since it uses as much as digits as its factorization.
5111400514327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 34.
The spelling of 5111400514327 in words is "five trillion, one hundred eleven billion, four hundred million, five hundred fourteen thousand, three hundred twenty-seven".
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