Base | Representation |
---|---|
bin | 100101001100001011111… |
… | …1011000010100100000001 |
3 | 200002122110010021020122010 |
4 | 1022120113323002210001 |
5 | 1132221133040411301 |
6 | 14512052255403133 |
7 | 1035200364556362 |
oct | 112302773024401 |
9 | 20078403236563 |
10 | 5111412435201 |
11 | 16a081307a096 |
12 | 6a67618234a9 |
13 | 2b10090a4a37 |
14 | 139572397b69 |
15 | 8ce5d8185d6 |
hex | 4a617ec2901 |
5111412435201 has 8 divisors (see below), whose sum is σ = 6822192240864. Its totient is φ = 3404120459840.
The previous prime is 5111412435167. The next prime is 5111412435263. The reversal of 5111412435201 is 1025342141115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5111412435201 - 217 = 5111412304129 is a prime.
It is a super-2 number, since 2×51114124352012 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5111412435301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 871954155 + ... + 871960016.
It is an arithmetic number, because the mean of its divisors is an integer number (852774030108).
Almost surely, 25111412435201 is an apocalyptic number.
It is an amenable number.
5111412435201 is a deficient number, since it is larger than the sum of its proper divisors (1710779805663).
5111412435201 is a wasteful number, since it uses less digits than its factorization.
5111412435201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1743915151.
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 5111412435201 its reverse (1025342141115), we get a palindrome (6136754576316).
The spelling of 5111412435201 in words is "five trillion, one hundred eleven billion, four hundred twelve million, four hundred thirty-five thousand, two hundred one".
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