Base | Representation |
---|---|
bin | 100101001100001100000… |
… | …0101010100110001110101 |
3 | 200002122110022100012220220 |
4 | 1022120120011110301311 |
5 | 1132221134233200003 |
6 | 14512052433244553 |
7 | 1035200426515524 |
oct | 112303005246165 |
9 | 20078408305826 |
10 | 5111415131253 |
11 | 16a0814650732 |
12 | 6a6762703759 |
13 | 2b1009809c32 |
14 | 13957289a4bb |
15 | 8ce5db9c353 |
hex | 4a618154c75 |
5111415131253 has 16 divisors (see below), whose sum is σ = 7338422525760. Its totient is φ = 3152803748096.
The previous prime is 5111415131243. The next prime is 5111415131261. The reversal of 5111415131253 is 3521315141115.
It is a cyclic number.
It is not a de Polignac number, because 5111415131253 - 224 = 5111398354037 is a prime.
It is a super-2 number, since 2×51114151312532 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5111415131243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 849351450 + ... + 849357467.
It is an arithmetic number, because the mean of its divisors is an integer number (458651407860).
Almost surely, 25111415131253 is an apocalyptic number.
It is an amenable number.
5111415131253 is a deficient number, since it is larger than the sum of its proper divisors (2227007394507).
5111415131253 is a wasteful number, since it uses less digits than its factorization.
5111415131253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1698708996.
The product of its digits is 9000, while the sum is 33.
The spelling of 5111415131253 in words is "five trillion, one hundred eleven billion, four hundred fifteen million, one hundred thirty-one thousand, two hundred fifty-three".
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