Base | Representation |
---|---|
bin | 101111100110101101… |
… | …011001011010100001 |
3 | 11212221022110022022021 |
4 | 233212231121122201 |
5 | 1314141004104023 |
6 | 35252042141441 |
7 | 3456453612514 |
oct | 574655313241 |
9 | 155838408267 |
10 | 51115300513 |
11 | 1a750288912 |
12 | 9aa64b1881 |
13 | 4a87b49a64 |
14 | 268c8d2d7b |
15 | 14e274e35d |
hex | be6b596a1 |
51115300513 has 2 divisors, whose sum is σ = 51115300514. Its totient is φ = 51115300512.
The previous prime is 51115300463. The next prime is 51115300519. The reversal of 51115300513 is 31500351115.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43818211584 + 7297088929 = 209328^2 + 85423^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51115300513 is a prime.
It is a super-2 number, since 2×511153005132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51115300519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25557650256 + 25557650257.
It is an arithmetic number, because the mean of its divisors is an integer number (25557650257).
Almost surely, 251115300513 is an apocalyptic number.
It is an amenable number.
51115300513 is a deficient number, since it is larger than the sum of its proper divisors (1).
51115300513 is an equidigital number, since it uses as much as digits as its factorization.
51115300513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1125, while the sum is 25.
Adding to 51115300513 its reverse (31500351115), we get a palindrome (82615651628).
The spelling of 51115300513 in words is "fifty-one billion, one hundred fifteen million, three hundred thousand, five hundred thirteen".
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