511160204941 has 4 divisors (see below), whose sum is σ = 513281201884. Its totient is φ = 509039208000.

The previous prime is 511160204917. The next prime is 511160205013. The reversal of 511160204941 is 149402061115.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 455827522500 + 55332682441 = 675150^2 + 235229^2 .

It is a cyclic number.

It is not a de Polignac number, because 511160204941 - 2¹⁷ = 511160073869 is a prime.

It is a super-2 number, since 2×511160204941² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 511160204897 and 511160204906.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (511160204441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1060498110 + ... + 1060498591.

It is an arithmetic number, because the mean of its divisors is an integer number (128320300471).

Almost surely, 2^511160204941 is an apocalyptic number.

It is an amenable number.

511160204941 is a deficient number, since it is larger than the sum of its proper divisors (2120996943).

511160204941 is a wasteful number, since it uses less digits than its factorization.

511160204941 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2120996942.

The product of its (nonzero) digits is 8640, while the sum is 34.

The spelling of 511160204941 in words is "five hundred eleven billion, one hundred sixty million, two hundred four thousand, nine hundred forty-one".