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511200112133 is a prime number
BaseRepresentation
bin1110111000001011110…
…01101010111000000101
31210212111102012100201102
413130011321222320011
531333414212042013
61030501520305445
751635005154444
oct7340571527005
91725442170642
10511200112133
11187887155517
12830a7a72285
133928a66b769
141aa56904d5b
15d46e04ed58
hex7705e6ae05

511200112133 has 2 divisors, whose sum is σ = 511200112134. Its totient is φ = 511200112132.

The previous prime is 511200112069. The next prime is 511200112183. The reversal of 511200112133 is 331211002115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 494183692324 + 17016419809 = 702982^2 + 130447^2 .

It is a cyclic number.

It is not a de Polignac number, because 511200112133 - 26 = 511200112069 is a prime.

It is a super-2 number, since 2×5112001121332 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511200112183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255600056066 + 255600056067.

It is an arithmetic number, because the mean of its divisors is an integer number (255600056067).

Almost surely, 2511200112133 is an apocalyptic number.

It is an amenable number.

511200112133 is a deficient number, since it is larger than the sum of its proper divisors (1).

511200112133 is an equidigital number, since it uses as much as digits as its factorization.

511200112133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 511200112133 its reverse (331211002115), we get a palindrome (842411114248).

The spelling of 511200112133 in words is "five hundred eleven billion, two hundred million, one hundred twelve thousand, one hundred thirty-three".