Base | Representation |
---|---|
bin | 100101001100011101110… |
… | …0110110011111001001011 |
3 | 200002200222211210011211022 |
4 | 1022120323212303321023 |
5 | 1132223344321041021 |
6 | 14512231523223055 |
7 | 1035221254334666 |
oct | 112307346637113 |
9 | 20080884704738 |
10 | 5112011112011 |
11 | 16a0aa0003911 |
12 | 6a68aa217a8b |
13 | 2b10a312927b |
14 | 1395cbab86dd |
15 | 8ce961741ab |
hex | 4a63b9b3e4b |
5112011112011 has 2 divisors, whose sum is σ = 5112011112012. Its totient is φ = 5112011112010.
The previous prime is 5112011111969. The next prime is 5112011112049. The reversal of 5112011112011 is 1102111102115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5112011112011 - 238 = 4837133205067 is a prime.
It is a super-2 number, since 2×51120111120112 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (5112011112211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556005556005 + 2556005556006.
It is an arithmetic number, because the mean of its divisors is an integer number (2556005556006).
Almost surely, 25112011112011 is an apocalyptic number.
5112011112011 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112011112011 is an equidigital number, since it uses as much as digits as its factorization.
5112011112011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 17.
Adding to 5112011112011 its reverse (1102111102115), we get a palindrome (6214122214126).
The spelling of 5112011112011 in words is "five trillion, one hundred twelve billion, eleven million, one hundred twelve thousand, eleven".
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