Base | Representation |
---|---|
bin | 1001100001011010… |
… | …01001110111011011 |
3 | 111012021100010022222 |
4 | 10300231021313123 |
5 | 40432200014210 |
6 | 2203134134255 |
7 | 240453136256 |
oct | 46055116733 |
9 | 14167303288 |
10 | 5112110555 |
11 | 2193720362 |
12 | ba805138b |
13 | 6361527b6 |
14 | 366d2609d |
15 | 1edbee655 |
hex | 130b49ddb |
5112110555 has 4 divisors (see below), whose sum is σ = 6134532672. Its totient is φ = 4089688440.
The previous prime is 5112110539. The next prime is 5112110609. The reversal of 5112110555 is 5550112115.
5112110555 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5550112115 = 5 ⋅1110022423.
It is not a de Polignac number, because 5112110555 - 24 = 5112110539 is a prime.
It is a super-2 number, since 2×51121105552 = 52267348653084816050, which contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511211051 + ... + 511211060.
It is an arithmetic number, because the mean of its divisors is an integer number (1533633168).
Almost surely, 25112110555 is an apocalyptic number.
5112110555 is a deficient number, since it is larger than the sum of its proper divisors (1022422117).
5112110555 is a wasteful number, since it uses less digits than its factorization.
5112110555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1022422116.
The product of its (nonzero) digits is 1250, while the sum is 26.
The square root of 5112110555 is about 71499.0248534901. The cubic root of 5112110555 is about 1722.6620211978.
The spelling of 5112110555 in words is "five billion, one hundred twelve million, one hundred ten thousand, five hundred fifty-five".
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