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5112133324189 is a prime number
BaseRepresentation
bin100101001100100001011…
…1001000000110110011101
3200002201022100202012102021
41022121002321000312131
51132224122112333224
614512252010500141
71035224300201503
oct112310271006635
920081270665367
105112133324189
1116a1052a96711
126a6923134651
132b10c2549078
1413960000c673
158cea1c651e4
hex4a642e40d9d

5112133324189 has 2 divisors, whose sum is σ = 5112133324190. Its totient is φ = 5112133324188.

The previous prime is 5112133324033. The next prime is 5112133324219. The reversal of 5112133324189 is 9814233312115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3533805944964 + 1578327379225 = 1879842^2 + 1256315^2 .

It is a cyclic number.

It is not a de Polignac number, because 5112133324189 - 211 = 5112133322141 is a prime.

It is a super-2 number, since 2×51121333241892 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5112133324589) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556066662094 + 2556066662095.

It is an arithmetic number, because the mean of its divisors is an integer number (2556066662095).

Almost surely, 25112133324189 is an apocalyptic number.

It is an amenable number.

5112133324189 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112133324189 is an equidigital number, since it uses as much as digits as its factorization.

5112133324189 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 155520, while the sum is 43.

The spelling of 5112133324189 in words is "five trillion, one hundred twelve billion, one hundred thirty-three million, three hundred twenty-four thousand, one hundred eighty-nine".