51121401 has 4 divisors (see below), whose sum is σ = 68161872. Its totient is φ = 34080932.

The previous prime is 51121393. The next prime is 51121423. The reversal of 51121401 is 10412115.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51121401 - 2³ = 51121393 is a prime.

It is a super-3 number, since 3×51121401³ (a number of 24 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (51121451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8520231 + ... + 8520236.

It is an arithmetic number, because the mean of its divisors is an integer number (17040468).

Almost surely, 2^51121401 is an apocalyptic number.

It is an amenable number.

51121401 is a deficient number, since it is larger than the sum of its proper divisors (17040471).

51121401 is a wasteful number, since it uses less digits than its factorization.

51121401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17040470.

The product of its (nonzero) digits is 40, while the sum is 15.

The square root of 51121401 is about 7149.9231464401. The cubic root of 51121401 is about 371.1369967488.

Adding to 51121401 its reverse (10412115), we get a palindrome (61533516).

It can be divided in two parts, 511 and 21401, that added together give a palindrome (21912).

The spelling of 51121401 in words is "fifty-one million, one hundred twenty-one thousand, four hundred one".