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5112144043503 = 37243435430643
BaseRepresentation
bin100101001100100001110…
…0001111001110111101111
3200002201100002220210112220
41022121003201321313233
51132224132333343003
614512253032330423
71035224460255240
oct112310341716757
920081302823486
105112144043503
1116a1059048252
126a6926843a13
132b10c4830163
141396015dccc7
158cea2b81353
hex4a643879def

5112144043503 has 8 divisors (see below), whose sum is σ = 7789933780608. Its totient is φ = 2921225167704.

The previous prime is 5112144043471. The next prime is 5112144043529. The reversal of 5112144043503 is 3053404412115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5112144043503 - 25 = 5112144043471 is a prime.

It is a super-2 number, since 2×51121440435032 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112144043603) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 121717715301 + ... + 121717715342.

It is an arithmetic number, because the mean of its divisors is an integer number (973741722576).

Almost surely, 25112144043503 is an apocalyptic number.

5112144043503 is a deficient number, since it is larger than the sum of its proper divisors (2677789737105).

5112144043503 is a wasteful number, since it uses less digits than its factorization.

5112144043503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 243435430653.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 5112144043503 its reverse (3053404412115), we get a palindrome (8165548455618).

The spelling of 5112144043503 in words is "five trillion, one hundred twelve billion, one hundred forty-four million, forty-three thousand, five hundred three".

Divisors: 1 3 7 21 243435430643 730306291929 1704048014501 5112144043503