Base | Representation |
---|---|
bin | 100101001100100011110… |
… | …1010000110110000100111 |
3 | 200002201111221020111202221 |
4 | 1022121013222012300213 |
5 | 1132224303101133221 |
6 | 14512303545013211 |
7 | 1035226261044043 |
oct | 112310752066047 |
9 | 20081457214687 |
10 | 5112213302311 |
11 | 16a1094152435 |
12 | 6a6945a84207 |
13 | 2b1105c9c4bb |
14 | 13960a8ab023 |
15 | 8cea8cb2541 |
hex | 4a647a86c27 |
5112213302311 has 2 divisors, whose sum is σ = 5112213302312. Its totient is φ = 5112213302310.
The previous prime is 5112213302279. The next prime is 5112213302327. The reversal of 5112213302311 is 1132033122115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5112213302311 - 25 = 5112213302279 is a prime.
It is a super-2 number, since 2×51122133023112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5112213302351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556106651155 + 2556106651156.
It is an arithmetic number, because the mean of its divisors is an integer number (2556106651156).
Almost surely, 25112213302311 is an apocalyptic number.
5112213302311 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112213302311 is an equidigital number, since it uses as much as digits as its factorization.
5112213302311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 5112213302311 its reverse (1132033122115), we get a palindrome (6244246424426).
The spelling of 5112213302311 in words is "five trillion, one hundred twelve billion, two hundred thirteen million, three hundred two thousand, three hundred eleven".
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