Base | Representation |
---|---|
bin | 101111100111001000… |
… | …101001011101010101 |
3 | 11212221210220020111012 |
4 | 233213020221131111 |
5 | 1314144321202432 |
6 | 35252455222005 |
7 | 3456601414403 |
oct | 574710513525 |
9 | 155853806435 |
10 | 51122444117 |
11 | 1a754317a18 |
12 | 9aa8977905 |
13 | 4a8947b444 |
14 | 268d832473 |
15 | 14e31b0cb2 |
hex | be7229755 |
51122444117 has 2 divisors, whose sum is σ = 51122444118. Its totient is φ = 51122444116.
The previous prime is 51122444099. The next prime is 51122444161. The reversal of 51122444117 is 71144422115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 36615205201 + 14507238916 = 191351^2 + 120446^2 .
It is a cyclic number.
It is not a de Polignac number, because 51122444117 - 210 = 51122443093 is a prime.
It is a super-2 number, since 2×511224441172 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51122444167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25561222058 + 25561222059.
It is an arithmetic number, because the mean of its divisors is an integer number (25561222059).
Almost surely, 251122444117 is an apocalyptic number.
It is an amenable number.
51122444117 is a deficient number, since it is larger than the sum of its proper divisors (1).
51122444117 is an equidigital number, since it uses as much as digits as its factorization.
51122444117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8960, while the sum is 32.
The spelling of 51122444117 in words is "fifty-one billion, one hundred twenty-two million, four hundred forty-four thousand, one hundred seventeen".
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