Base | Representation |
---|---|
bin | 100101001100100101000… |
… | …0001100101101001000111 |
3 | 200002201121200221222222120 |
4 | 1022121022001211221013 |
5 | 1132224343232400201 |
6 | 14512311524101023 |
7 | 1035230252424246 |
oct | 112311201455107 |
9 | 20081550858876 |
10 | 5112253012551 |
11 | 16a1104605313 |
12 | 6a6957234773 |
13 | 2b1111294199 |
14 | 139611c8695d |
15 | 8ceac508536 |
hex | 4a64a065a47 |
5112253012551 has 8 divisors (see below), whose sum is σ = 7175091947520. Its totient is φ = 3228791376312.
The previous prime is 5112253012541. The next prime is 5112253012577. The reversal of 5112253012551 is 1552103522115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5112253012551 - 213 = 5112253004359 is a prime.
It is a super-2 number, since 2×51122530125512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5112253012541) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44844324615 + ... + 44844324728.
It is an arithmetic number, because the mean of its divisors is an integer number (896886493440).
Almost surely, 25112253012551 is an apocalyptic number.
5112253012551 is a deficient number, since it is larger than the sum of its proper divisors (2062838934969).
5112253012551 is a wasteful number, since it uses less digits than its factorization.
5112253012551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89688649365.
The product of its (nonzero) digits is 15000, while the sum is 33.
Adding to 5112253012551 its reverse (1552103522115), we get a palindrome (6664356534666).
The spelling of 5112253012551 in words is "five trillion, one hundred twelve billion, two hundred fifty-three million, twelve thousand, five hundred fifty-one".
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