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5112253012551 = 31989688649343
BaseRepresentation
bin100101001100100101000…
…0001100101101001000111
3200002201121200221222222120
41022121022001211221013
51132224343232400201
614512311524101023
71035230252424246
oct112311201455107
920081550858876
105112253012551
1116a1104605313
126a6957234773
132b1111294199
14139611c8695d
158ceac508536
hex4a64a065a47

5112253012551 has 8 divisors (see below), whose sum is σ = 7175091947520. Its totient is φ = 3228791376312.

The previous prime is 5112253012541. The next prime is 5112253012577. The reversal of 5112253012551 is 1552103522115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5112253012551 - 213 = 5112253004359 is a prime.

It is a super-2 number, since 2×51122530125512 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112253012541) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44844324615 + ... + 44844324728.

It is an arithmetic number, because the mean of its divisors is an integer number (896886493440).

Almost surely, 25112253012551 is an apocalyptic number.

5112253012551 is a deficient number, since it is larger than the sum of its proper divisors (2062838934969).

5112253012551 is a wasteful number, since it uses less digits than its factorization.

5112253012551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89688649365.

The product of its (nonzero) digits is 15000, while the sum is 33.

Adding to 5112253012551 its reverse (1552103522115), we get a palindrome (6664356534666).

The spelling of 5112253012551 in words is "five trillion, one hundred twelve billion, two hundred fifty-three million, twelve thousand, five hundred fifty-one".

Divisors: 1 3 19 57 89688649343 269065948029 1704084337517 5112253012551