Base | Representation |
---|---|
bin | 100101001100101001110… |
… | …0100101101101100111111 |
3 | 200002202000212102011012000 |
4 | 1022121103210231230333 |
5 | 1132230210240344201 |
6 | 14512335445513343 |
7 | 1035234236220345 |
oct | 112312344555477 |
9 | 20082025364160 |
10 | 5112413215551 |
11 | 16a1186a86194 |
12 | 6a69a0a12853 |
13 | 2b1138526165 |
14 | 139629269995 |
15 | 8cebb600d86 |
hex | 4a65392db3f |
5112413215551 has 8 divisors (see below), whose sum is σ = 7573945504560. Its totient is φ = 3408275477016.
The previous prime is 5112413215501. The next prime is 5112413215627. The reversal of 5112413215551 is 1555123142115.
5112413215551 is a `hidden beast` number, since 51 + 1 + 2 + 41 + 3 + 2 + 15 + 551 = 666.
It is not a de Polignac number, because 5112413215551 - 26 = 5112413215487 is a prime.
It is a super-2 number, since 2×51124132155512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5112413215501) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 94674318780 + ... + 94674318833.
It is an arithmetic number, because the mean of its divisors is an integer number (946743188070).
Almost surely, 25112413215551 is an apocalyptic number.
5112413215551 is a deficient number, since it is larger than the sum of its proper divisors (2461532289009).
5112413215551 is a wasteful number, since it uses less digits than its factorization.
5112413215551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 189348637622 (or 189348637616 counting only the distinct ones).
The product of its digits is 30000, while the sum is 36.
Adding to 5112413215551 its reverse (1555123142115), we get a palindrome (6667536357666).
The spelling of 5112413215551 in words is "five trillion, one hundred twelve billion, four hundred thirteen million, two hundred fifteen thousand, five hundred fifty-one".
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