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5112430342121 is a prime number
BaseRepresentation
bin100101001100101010010…
…0110000010111111101001
3200002202002001122021102102
41022121110212002333221
51132230224131421441
614512341300543145
71035234534621134
oct112312446027751
920082061567372
105112430342121
1116a1195713683
126a69a66b1ab5
132b113bc4171b
1413962b64721b
158cebcd8569b
hex4a654982fe9

5112430342121 has 2 divisors, whose sum is σ = 5112430342122. Its totient is φ = 5112430342120.

The previous prime is 5112430342109. The next prime is 5112430342127. The reversal of 5112430342121 is 1212430342115.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3261415671721 + 1851014670400 = 1805939^2 + 1360520^2 .

It is a cyclic number.

It is not a de Polignac number, because 5112430342121 - 210 = 5112430341097 is a prime.

It is a super-3 number, since 3×51124303421213 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (5112430342127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556215171060 + 2556215171061.

It is an arithmetic number, because the mean of its divisors is an integer number (2556215171061).

Almost surely, 25112430342121 is an apocalyptic number.

It is an amenable number.

5112430342121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112430342121 is an equidigital number, since it uses as much as digits as its factorization.

5112430342121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 5112430342121 its reverse (1212430342115), we get a palindrome (6324860684236).

The spelling of 5112430342121 in words is "five trillion, one hundred twelve billion, four hundred thirty million, three hundred forty-two thousand, one hundred twenty-one".