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5112443050534 = 22556221525267
BaseRepresentation
bin100101001100101010101…
…0110100001101000100110
3200002202002221112221002101
41022121111112201220212
51132230240410104114
614512342433202314
71035235050630661
oct112312526415046
920082087487071
105112443050534
1116a11a19036a6
126a69aaa0039a
132b1141770cb1
1413962d1d46d8
158cebe045d74
hex4a6555a1a26

5112443050534 has 4 divisors (see below), whose sum is σ = 7668664575804. Its totient is φ = 2556221525266.

The previous prime is 5112443050489. The next prime is 5112443050571. The reversal of 5112443050534 is 4350503442115.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×51124430505342 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5112443050493 and 5112443050502.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278110762632 + ... + 1278110762635.

It is an arithmetic number, because the mean of its divisors is an integer number (1917166143951).

Almost surely, 25112443050534 is an apocalyptic number.

5112443050534 is a deficient number, since it is larger than the sum of its proper divisors (2556221525270).

5112443050534 is a wasteful number, since it uses less digits than its factorization.

5112443050534 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2556221525269.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 5112443050534 its reverse (4350503442115), we get a palindrome (9462946492649).

The spelling of 5112443050534 in words is "five trillion, one hundred twelve billion, four hundred forty-three million, fifty thousand, five hundred thirty-four".

Divisors: 1 2 2556221525267 5112443050534