Base | Representation |
---|---|
bin | 1001100001011101… |
… | …00110000110001101 |
3 | 111012022001022112202 |
4 | 10300232212012031 |
5 | 40432244111313 |
6 | 2203150211245 |
7 | 240456301541 |
oct | 46056460615 |
9 | 14168038482 |
10 | 5112488333 |
11 | 2193959177 |
12 | ba81b3b25 |
13 | 636255734 |
14 | 366dc3a21 |
15 | 1edc76558 |
hex | 130ba618d |
5112488333 has 2 divisors, whose sum is σ = 5112488334. Its totient is φ = 5112488332.
The previous prime is 5112488299. The next prime is 5112488347. The reversal of 5112488333 is 3338842115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4390652644 + 721835689 = 66262^2 + 26867^2 .
It is a cyclic number.
It is not a de Polignac number, because 5112488333 - 228 = 4844052877 is a prime.
It is a super-2 number, since 2×51124883332 = 52275073910122237778, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5112488383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556244166 + 2556244167.
It is an arithmetic number, because the mean of its divisors is an integer number (2556244167).
Almost surely, 25112488333 is an apocalyptic number.
It is an amenable number.
5112488333 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112488333 is an equidigital number, since it uses as much as digits as its factorization.
5112488333 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 69120, while the sum is 38.
The square root of 5112488333 is about 71501.6666449112. Note that the first 4 decimals coincide. The cubic root of 5112488333 is about 1722.7044542774.
The spelling of 5112488333 in words is "five billion, one hundred twelve million, four hundred eighty-eight thousand, three hundred thirty-three".
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