Base | Representation |
---|---|
bin | 10111001111111100000001… |
… | …01110110001110011011011 |
3 | 20201000111221222200100012020 |
4 | 23213332000232301303123 |
5 | 23200113304300024210 |
6 | 300422323331545523 |
7 | 13524446004213015 |
oct | 1347760056616333 |
9 | 221014858610166 |
10 | 51125155470555 |
11 | 15321069484471 |
12 | 589849315b2a3 |
13 | 226b109cca66a |
14 | c8a6839691b5 |
15 | 5d9d38c93770 |
hex | 2e7f80bb1cdb |
51125155470555 has 32 divisors (see below), whose sum is σ = 86164867895040. Its totient is φ = 25813854633600.
The previous prime is 51125155470553. The next prime is 51125155470611. The reversal of 51125155470555 is 55507455152115.
It is not a de Polignac number, because 51125155470555 - 21 = 51125155470553 is a prime.
It is a super-2 number, since 2×511251554705552 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51125155470498 and 51125155470507.
It is not an unprimeable number, because it can be changed into a prime (51125155470553) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 61401252 + ... + 62228321.
It is an arithmetic number, because the mean of its divisors is an integer number (2692652121720).
Almost surely, 251125155470555 is an apocalyptic number.
51125155470555 is a deficient number, since it is larger than the sum of its proper divisors (35039712424485).
51125155470555 is a wasteful number, since it uses less digits than its factorization.
51125155470555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123631051.
The product of its (nonzero) digits is 4375000, while the sum is 51.
The spelling of 51125155470555 in words is "fifty-one trillion, one hundred twenty-five billion, one hundred fifty-five million, four hundred seventy thousand, five hundred fifty-five".
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