5112530454013 has 4 divisors (see below), whose sum is σ = 5124732197760. Its totient is φ = 5100328710268.

The previous prime is 5112530454011. The next prime is 5112530454071. The reversal of 5112530454013 is 3104540352115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5112530454013 - 2¹ = 5112530454011 is a prime.

It is a super-2 number, since 2×5112530454013² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5112530454013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112530454011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6100871245 + ... + 6100872082.

It is an arithmetic number, because the mean of its divisors is an integer number (1281183049440).

Almost surely, 2^{5112530454013} is an apocalyptic number.

It is an amenable number.

5112530454013 is a deficient number, since it is larger than the sum of its proper divisors (12201743747).

5112530454013 is a wasteful number, since it uses less digits than its factorization.

5112530454013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12201743746.

The product of its (nonzero) digits is 36000, while the sum is 34.

The spelling of 5112530454013 in words is "five trillion, one hundred twelve billion, five hundred thirty million, four hundred fifty-four thousand, thirteen".