Base | Representation |
---|---|
bin | 100101001100101101010… |
… | …1111101111000001000011 |
3 | 200002202100020211112012021 |
4 | 1022121122233233001003 |
5 | 1132230432041420102 |
6 | 14512355424542311 |
7 | 1035240230053216 |
oct | 112313257570103 |
9 | 20082306745167 |
10 | 5112533545027 |
11 | 16a12389a2537 |
12 | 6a6a15181997 |
13 | 2b115743702c |
14 | 13963b22d77d |
15 | 8cec6e6e137 |
hex | 4a65abef043 |
5112533545027 has 2 divisors, whose sum is σ = 5112533545028. Its totient is φ = 5112533545026.
The previous prime is 5112533545019. The next prime is 5112533545033. The reversal of 5112533545027 is 7205453352115.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5112533545027 - 23 = 5112533545019 is a prime.
It is a super-2 number, since 2×51125335450272 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5112533545037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556266772513 + 2556266772514.
It is an arithmetic number, because the mean of its divisors is an integer number (2556266772514).
Almost surely, 25112533545027 is an apocalyptic number.
5112533545027 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112533545027 is an equidigital number, since it uses as much as digits as its factorization.
5112533545027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 630000, while the sum is 43.
The spelling of 5112533545027 in words is "five trillion, one hundred twelve billion, five hundred thirty-three million, five hundred forty-five thousand, twenty-seven".
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