Base | Representation |
---|---|
bin | 101111100111011010… |
… | …000000100010001001 |
3 | 11212222010110110020102 |
4 | 233213122000202021 |
5 | 1314202002320311 |
6 | 35253140535145 |
7 | 3456655200461 |
oct | 574732004211 |
9 | 155863413212 |
10 | 51126995081 |
11 | 1a756946148 |
12 | 9aaa3b14b5 |
13 | 4a8a3b2a16 |
14 | 2690298ba1 |
15 | 14e37ae43b |
hex | be7680889 |
51126995081 has 2 divisors, whose sum is σ = 51126995082. Its totient is φ = 51126995080.
The previous prime is 51126995077. The next prime is 51126995189. The reversal of 51126995081 is 18059962115.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40568405056 + 10558590025 = 201416^2 + 102755^2 .
It is a cyclic number.
It is not a de Polignac number, because 51126995081 - 22 = 51126995077 is a prime.
It is a super-2 number, since 2×511269950812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51126995581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25563497540 + 25563497541.
It is an arithmetic number, because the mean of its divisors is an integer number (25563497541).
Almost surely, 251126995081 is an apocalyptic number.
It is an amenable number.
51126995081 is a deficient number, since it is larger than the sum of its proper divisors (1).
51126995081 is an equidigital number, since it uses as much as digits as its factorization.
51126995081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 47.
The spelling of 51126995081 in words is "fifty-one billion, one hundred twenty-six million, nine hundred ninety-five thousand, eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •