5112727437 has 4 divisors (see below), whose sum is σ = 6816969920. Its totient is φ = 3408484956.

The previous prime is 5112727387. The next prime is 5112727457. The reversal of 5112727437 is 7347272115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5112727437 - 2¹⁰ = 5112726413 is a prime.

It is a super-2 number, since 2×5112727437² = 52279963690105177938, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5112727395 and 5112727404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112727457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852121237 + ... + 852121242.

It is an arithmetic number, because the mean of its divisors is an integer number (1704242480).

Almost surely, 2^5112727437 is an apocalyptic number.

It is an amenable number.

5112727437 is a deficient number, since it is larger than the sum of its proper divisors (1704242483).

5112727437 is a wasteful number, since it uses less digits than its factorization.

5112727437 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1704242482.

The product of its digits is 82320, while the sum is 39.

The square root of 5112727437 is about 71503.3386423319. The cubic root of 5112727437 is about 1722.7313100261.

The spelling of 5112727437 in words is "five billion, one hundred twelve million, seven hundred twenty-seven thousand, four hundred thirty-seven".