Base | Representation |
---|---|
bin | 100101001100111011111… |
… | …0111110100010011101011 |
3 | 200002210121022022221001222 |
4 | 1022121313313310103223 |
5 | 1132232432140444430 |
6 | 14512520122332255 |
7 | 1035255312431321 |
oct | 112316767642353 |
9 | 20083538287058 |
10 | 5113022203115 |
11 | 16a14698125a2 |
12 | 6a6b3095a08b |
13 | 2b120474a828 |
14 | 1396860b1d11 |
15 | 8d004ce69e5 |
hex | 4a677df44eb |
5113022203115 has 8 divisors (see below), whose sum is σ = 6135911925360. Its totient is φ = 4090227574752.
The previous prime is 5113022203087. The next prime is 5113022203123.
5113022203115 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5113022203115 - 214 = 5113022186731 is a prime.
It is a super-2 number, since 2×51130222031152 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23655125 + ... + 23870294.
It is an arithmetic number, because the mean of its divisors is an integer number (766988990670).
Almost surely, 25113022203115 is an apocalyptic number.
5113022203115 is a deficient number, since it is larger than the sum of its proper divisors (1022889722245).
5113022203115 is a wasteful number, since it uses less digits than its factorization.
5113022203115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47546941.
The product of its (nonzero) digits is 1800, while the sum is 26.
The spelling of 5113022203115 in words is "five trillion, one hundred thirteen billion, twenty-two million, two hundred three thousand, one hundred fifteen".
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